Let f(x) = ln(x) and find the equation of the tangent line to f(x) at a "nice" point near 1.08. Then use this?

Use differentials (or equivalently, a linear approximation) to approximate ln(1.08) as follows: Let f(x) = ln(x) and find the equation of the tangent line to f(x) at a "nice" point near 1.08. Then use this to approximate ln(1.08).